Question

The midpoint of AB is M(0, -3)M(0,−3). If the coordinates of AA are (6, -5)(6,−5), what are the coordinates of BB?

Answer 1

Explanation:

Mid point of AB is (0, -3)

Coordinate of A is (6, -5)

By using mid point formula, if P(x, y) and Q (x′, y′), then mid point of P= (x + x′)/2 , (y + y′)/2

So, ( 0, -3)= 6+x/2, -5+y/2

0=6+x/2

0=6+x, x = -6

and, -3= -5+y/2, -6= -5+y....

y = -1

so the coordinate is (-6, -1)

Answer 2

Finding the Midpoint

To find the midpoint of two points, we can use the following formula:

`midpoint=((x_1+x_2)/(2),(y_1+y_2)/(2))`

• 
  `(x_1,y_1)` and
  `(x_2,y_2)` are two endpoints

Solving the Question

We're given:

• AA = (6, -5)
• AB = (0, -3)
• BB =
  `(x_2,y_2)`

Plug the information into the formula:

`midpoint=((x_1+x_2)/(2),(y_1+y_2)/(2))\\\\(0,-3)=((6+x_2)/(2),(-5+y_2)/(2))`

If
`(6+x_2)/(2)` must equal 0, then
`x_2` must be -6.

If
`(-5+y_2)/(2)` must equal -3, then
`-5+y_2` must equal -6, making
`y_2` equal to -1.

Therefore, BB is (-6,-1).

Answer

(-6, -1)