Question

Margaret drove to a business appointment at 60 mph. Her average speed on the return trip was 50 mph. The return trip took one fifth 1 5 hr longer because of heavy traffic. How far did she travel to the​ appointment?

Answer 1

She traveled 60 miles to the appointment place.

Explanation:

Let the distance to appoint be s and time for appointment trip be t.

The return trip took one fifth hr longer because of heavy traffic.

Time for return trip = t + one fifth hour = (t + 0.2) hr

Speed of appointment trip = 60 mph

Speed of return trip = 50 mph

We have

s = 60 t and

s = 50 (t + 0.2)

s = 50 t + 10

60t = 50 t + 10

10 t = 10

t = 1 hour

Distance to appointment = 60 t = 60 x 1 = 60 miles

She traveled 60 miles to the appointment place.