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Write -4i + (1/4-5i)-(-3/4+8i)+17i as a complex number in standard form​

User Chuck Hays
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1 Answer

6 votes

Answer:

1

Explanation:


-4i+\left((1)/(4)-5i\right)-\left(-(3)/(4)+8i\right)+17i\\\\=-4i+(1)/(4)-5i+(3)/(4)-8i+17i\\\\=\left((1)/(4)+(3)/(4)\right)+(-4i-5i-8i+17i)\\\\=(1+3)/(4)+(-4-5-8+17)i\\\\=(4)/(4)+0i\\\\=1

User Saif Siddiqui
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