Question

the refueling planes were able to air-transfer a total of 687 gallons of fuel to the plane in 9 refueling transfers. Assume that the refueling nozzle had a diameter of 1.45 inches and each refueling took 2.41 minutes to perform. Calculate the velocity of the fuel through the nozzle. Assume that the fuel filled the entire cross-sectional area of the nozzle.

Answer 1

the velocity of the fuel through the nozzle v= 6.45 ft/s

Step-by-step explanation:

Given values

Volume = 687 gallons=
`2.6 m^3`

9 refueling transfers

dia of nozzle d= 1.45 inches

each refueling took 2.41 minutes to perform. t= 2.41×60×9= 1247.4 sec

Volume of fuel pumped in time t is give by

V= Avt

A= area of mouth of pipe

v= flow rate

t= time

A= πr^2

A=
`\pi* ((0.0368)/(2) )^2 = 0.00106 m^2`

now substituting the values in equation 1 we get

`2.6= 0.00106* v *1247.4`

v= 1.966 m/sec

v= 6.45 ft/s

the velocity of the fuel through the nozzle v= 6.45 ft/s