An air-track glider attached to a spring oscillates between the 13.0 cm mark and the 63.0 cm mark on the track. The glider completes 15.0 oscillations in 32.0 s . What are the (…

Question

asked May 10, 2020 130k views

1 Answer

Katsu · Answer 1 · 2020-05-16T07:51:39+0000

Answer:

(A) = 2.13 s

(B) = 0.47 Hz

(C) = 0.25 m

(D) = 0.74 m/s

Step-by-step explanation:

number of oscillations (n) = 15

time (t) = 32 secs

start point (L1) = 13 cm = 0.13 m

End point (L2) = 63 cm = 0.63 m

(A) period = time / number of oscillation

= 32 / 15 = 2.13 s

(B) frequency = 1 / period

= 1 / 2.13 = 0.47 Hz

(C) Amplitude = 0.5 ( L2 - L1 )

= 0.5 ( 0.63 - 0.13 )

= 0.25 m

(D) max speed = (2π / T) x A

= (2π / 2.13) x 0.25

= 0.74 m/s