Question

Match each transition metal ion with its condensed ground-state electron configuration. A [Ar]3d2 B [Ar]4s23d3 C [Kr]4d10 D [Xe] E [Ar]3d6 F [Ar]3d5 G [Xe]4f145d10 Mn2+ Hg2+ La3+ Fe3+ Ag+ Co3+

Answer 1

`Mn^(2+)` : - F .
`[Ar]3d^(5)`

`Hg^(2+)` : - G.
`[Xe]4f^(14)5d^(10)`

`La^(3+)` : - D.
`[Xe]`

`Fe^(3+)` : - F.
`[Ar]3d^(5)`

`Ag^(+)` : - C.
`[Kr]4d^(10)`

`Co^(3+)` : - E.
`[Ar]3d^(6)`

Step-by-step explanation:

The electronic configuration of the element Mn is:-

`[Ar]3d^(5)4s^2`

For,
`Mn^(2+)`, 2 electrons are lost, thus the configuration is:-

`[Ar]3d^(5)`

The electronic configuration of the element Hg is:-

`[Xe]4f^(14)5d^(10)6s^2`

For,
`Hg^(2+)`, 2 electrons are lost, thus the configuration is:-

`[Xe]4f^(14)5d^(10)`

The electronic configuration of the element La is:-

`[Xe]5d^(1)6s^2`

For,
`La^(3+)`, 3 electrons are lost, thus the configuration is:-

`[Xe]`

The electronic configuration of the element Fe is:-

`[Ar]3d^(6)4s^2`

For,
`Fe^(3+)`, 3 electrons are lost, thus the configuration is:-

`[Ar]3d^(5)`

The electronic configuration of the element Ag is:-

`[Kr]4d^(10)5s^1`

For,
`Ag^(+)`, 1 electron is lost, thus the configuration is:-

`[Kr]4d^(10)`

The electronic configuration of the element Co is:-

`[Ar]3d^(7)4s^2`

For,
`Co^(3+)`, 3 electrons are lost, thus the configuration is:-

`[Ar]3d^(6)`