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27 votes
27 votes
Acceleration due to gravity on Mars is -3.7 m/s2. If you throw a Martian rock upwards with a velocity of 21.1 m/s, how long will it take to land back in your hand, at the same height from which it was thrown?

User Mark Hildreth
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1 Answer

5 votes
5 votes

Answer:

5.7 seconds

Step-by-step explanation:

1. We know that :

acceleration = change in velocity / time

2. We have been given the following :
acceleration = - 3.7 m/s^2
initial velocity = 21.1 m/s
final velocity = 0 (at the rock's max greatest height its velocity is 0)
time = ?

3. Subsitute the values + rearrange for t :
-3.7 = 0 - 21.1/t
t = 0-21.1/-3.7
t = -21.1/-3.7
t = 5.7 seconds (1.d.p)

User Abhijeet Sharma
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2.4k points