if 3.99 x 10 ^ 13 was written in standard notation how many zeros does it contain before the decimal point

Stealththeninja asked Apr 24, 2023

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Stealththeninja asked Apr 24, 2023

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12 votes

Answer:

11 zeros

Explanation:

10^13 = 100 000 000 000 000

Round the two first numbers(which makes 11 zeros left), then lastly the zeros

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