Question

The gauge pressure in your car tires is 2.50×10^5N/m22.50×10^5⁢N/m^2 at a temperature of 35.0ºC when you drive it onto a ferry boat to Alaska. What is their gauge pressure later, when their temperature has dropped to -40.0ºC?

Answer 1

Answer:
`3.30* 10^5N/m^2`

Step-by-step explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

`P\propto T` (At constant volume and number of moles)

`{P_1* T_1}={P_2* T_2}`

where,

`P_1` = initial pressure of gas =
`2.50* 10^5N/m^2`

`P_2` = final pressure of gas = ?

`T_1` = initial temperature of gas =
`35^0C=(35+273)K=308K`

`T_2` = final temperature of gas =
`-40^0C=(-40+273)K=233K`

`{2.50* 10^5N/m^2* 308}={P_2* 233}`

`P_2=3.30* 10^5N/m^2`

Therefore, the final gauge pressure in the car tires is
`3.30* 10^5N/m^2`