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What is the distance between the points A(2, -1) and B(-4, 2)

A). 2
B).
\sqrt[3]{5}
C).
\sqrt[5]{3}
D).4

1 Answer

4 votes

The distance between two points A(2, -1) and B(-4, 2) is
3 √(5) units

Solution:

Given that two points are A(2, -1) and B(-4, 2)

To find: distance between two points

The distance between two points
A(x_1, y_1) and
B(x_2, y_2) is given as:


Distance(A, B) = d = √((x_2 - x_1)^2+ (y_2 - y_1)^2)

Here in this problem,


x_1 = 2 ; y_1 = -1 ; x_2 = -4 ; y_2 = 2

Substituting the values in given formula, we get


d = √((-4-2)^2+(2-(-1))^2)\\\\d = √((-6)^2 + (3)^2)\\\\d = √(36 + 9)\\\\d = √(45)

On simplification we get,


d = √(45) = √(3 * 3 * 5)\\\\d = 3√(5)

Thus the distance between two points A(2, -1) and B(-4, 2) is
3 √(5) units

User Ben Lindsay
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