Answer : The thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole
Explanation :
First we have to calculate the heat released by the combustion.
![q=c* \Delta T](https://img.qammunity.org/2020/formulas/chemistry/high-school/b0hgnbl4wraewgwofr48ly94kdb5opzyug.png)
where,
q = heat released = ?
= specific heat of calorimeter =
![3.640kJ/^oC](https://img.qammunity.org/2020/formulas/chemistry/high-school/n6z3zj8rs779d12a768e85beckkgvtatgx.png)
= change in temperature =
![19.35^oC](https://img.qammunity.org/2020/formulas/chemistry/high-school/tgxa9tn5gdv4xwde2lgtozmvm5mvj3gdvv.png)
Now put all the given values in the above formula, we get:
![q=3.640kJ/^oC* (19.35)^oC](https://img.qammunity.org/2020/formulas/chemistry/high-school/79irynpn5s7zxufp5oowh0bxlv5rb85h1m.png)
![q=70.43kJ](https://img.qammunity.org/2020/formulas/chemistry/high-school/62vkd5a35agxi1uyzdsdq3l89jugvzrwls.png)
Thus, the heat released by the combustion = 70.43 kJ
Now we have to calculate the molar enthalpy combustion.
![\Delta H=-(q)/(n)](https://img.qammunity.org/2020/formulas/chemistry/high-school/5m040cry01hjobovy2jvq44982v0mvxp0c.png)
where,
= molar enthalpy combustion = ?
q = heat released = 70.43 kJ
n = number of moles cymene =
![\frac{\text{Mass of cymene}}{\text{Molar mass of cymene}}=(1.608g)/(164.22g/mol)=0.009792mole](https://img.qammunity.org/2020/formulas/chemistry/high-school/zenyz7a99vj0nq4pkimoimklwfw6mjsl2l.png)
![\Delta H=-(70.43kJ)/(0.009792mole)=-7193kJ/mole](https://img.qammunity.org/2020/formulas/chemistry/high-school/ryu88m2i0yqd01yxni1qglomd333l6m772.png)
Therefore, the thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole