Question

An ice skater starts with a velocity of 2.25 m/s in a 50.0 degree direction. After 8.33s, she is moving 4.65 m/s in a 120 degree direction. What is the y-component of her acceleration? PLEASE HELP

Answer 1

jk

Step-by-step explanation:

Lets decompose the initial velocity into its components:

Vi = 2.25 m/s

Vix = Vi x cos(50)

Viy = Vi x sin(50) = 2.25 x sin(50) = 1.724

Then decompose the final velocity:

Vf = 4.65

Vfx = Vf x cos(120)

Vfy = Vf x sin(120) = 4.65 x sin(120) = 4.027

After that we can use:

Vfy = Viy + ay*t

ay = (Vfy - Viy)/t

ay = (4.027 - 1.724) / 8.33

ay = 0.276