Question

If 3.50 moles of He occupy 86.163 L at 300 K and a pressure of 1 atmosphere, what will the volume be for 3.50 moles at 250 K and 1 atmosphere?

Answer 1

Answer: The final volume will be 71.8 L

Step-by-step explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1\text{ and }T_1` are the initial volume and temperature of the gas.

`V_2\text{ and }T_2` are the final volume and temperature of the gas.

We are given:

`V_1=86.163L\\T_1=300K\\V_2=?L\\T_2=250K`

Putting values in above equation, we get:

`(86.163L)/(300K)=(V_2)/(250)\\\\V_2=(86.163* 250)/(300)=71.8L`

Hence, the final volume will be 71.8 L