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A uniform charge density of 500 nC/m3 is distributed throughout a spherical volume (radius = 16 cm). Consider a cubical (4.0 cm along the edge) surface completely inside the sphere. Determine the electric flux through this surface.

User SteveGoob
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1 Answer

3 votes

Answer:

3.61581 Nm²/C

Step-by-step explanation:


\epsilon_0 = Permittivity of free space =
8.85* 10^(-12)\ F/m


\rho = Charge density = 500 nC/m³

v = Volume =
0.04^3\ m^3

From Gauss' Law we have


\phi=(Q)/(\epsilon)\\\Rightarrow \phi=(\rho v)/(\epsilon)\\\Rightarrow \phi=(500* 10^(-9)* 0.04^3)/(8.85* 10^(-12))\\\Rightarrow \phi=3.61581\ Nm^2/C

The electric flux through this surface is 3.61581 Nm²/C

User Xeolabs
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