To solve this problem we must basically resort to the kinematic equations of movement. For which speed is defined as the distance traveled in a given time. Mathematically this can be expressed as
![v = (d)/(t)](https://img.qammunity.org/2020/formulas/biology/middle-school/c18b0zisytvs9saczm5k29bklhyrm8c52i.png)
Where
d = Distance
t = time
For which clearing the time we will have the expression
![t = (d)/(v)](https://img.qammunity.org/2020/formulas/physics/middle-school/7ws40aorg1oplkn9se8cdw1zohlivftc1o.png)
Since we have two 'fluids' in which the sound travels at different speeds we will have that for the rock the time elapsed to feel the explosion will be:
![t = (1300m)/(3000m/s)](https://img.qammunity.org/2020/formulas/physics/college/ff8ehhnlcha1hbtt1v00jo5be6yimf1tvy.png)
![t = 0.433s](https://img.qammunity.org/2020/formulas/physics/college/kvugxp2o52rcwvz0lj19sls31w9mngcu9u.png)
In the case of the atmosphere -composite of air- the average speed of sound is 343m / s, therefore it will take
![t = (1300m)/(343m/s)](https://img.qammunity.org/2020/formulas/physics/college/bjjgkkspy0k4so4ofocgi2xdx6hgk6i6y1.png)
![t = 3.79s](https://img.qammunity.org/2020/formulas/physics/college/u9hecv4ip06ezf9fhzw8kev0h5uv6u1thc.png)
The total difference between the two times would be
![\Delta t = 3.79s-0.433s](https://img.qammunity.org/2020/formulas/physics/college/euv51lxngm1p5h7ag6n84ac04uaa7k765v.png)
![\Delta t = 3.357s](https://img.qammunity.org/2020/formulas/physics/college/dsd9h4ncdr7ikiowxterh6run5dhz4dwr1.png)
Therefore 3.357s will pass between when they feel the explosion and when they hear it