Question

What are the solutions of x^2+8x-8 ? A. x=-11 or x=1 B. x=-11 or x=-1 C. x=-8 or x=-2 D. x=-8 or x=2

Answer 1

The solutions are

`x=-4+2√(6)`

`x=-4-2√(6)`

Explanation:

we know that

The formula to solve a quadratic equation of the form

`ax^(2) +bx+c=0`

is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`x^(2) +8x-8=0`

so

`a=1\\b=8\\c=-8`

substitute in the formula

`x=\frac{-8(+/-)\sqrt{8^(2)-4(1)(-8)}} {2(1)}`

`x=\frac{-8(+/-)√(96)} {2}`

`x=\frac{-8(+/-)4√(6)} {2}`

`x=-4(+/-)2√(6)`