Answer:
Option c
Step-by-step explanation:
In this experiment we get to know that the power depends on both work done and amount of time taken
Here as height of 1 stair and number of stairs are same, the displacement in calculation of work will be the same and therefore work depends on the force
For climbing internally we require a force equal to the (mass of the body) × (acceleration due to gravity) and therefore the force we apply will be dependent on the mass of the body as acceleration due to gravity will be same for both
Work done in case of student 1 will be (500 × g) = (500 × g) × 20 ×0·15
Work done in case of student 2 will be (700 × g) = (700 × g) × 20 ×0·15
Power is defined as work done per unit time
∴ Power = (Work done) ÷ (time taken)
Power required in case of student 1 will be ((500 × g) × 20 ×0·15) ÷ 15 = ((100 × g) × 20 ×0·15) ÷ 3
Power required in case of student 2 will be ((700 × g) × 20 ×0·15) ÷ 21 = ((100 × g) × 20 ×0·15) ÷ 3
From above we can say that the power required in case of both the students are same