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Does anyone understand this?. I also have to show my work.

Does anyone understand this?. I also have to show my work.-example-1
User Dan Wich
by
8.1k points

1 Answer

4 votes

Answer:

Ans A). The graph is shown.

Ans B). 18.3333 C temperature when F is 65 temperature

Ans C). 32 F when the line crosses the horizontal axis

Ans D). Slope of line C=
(5)/(9)(F -32) is
(5)/(9)

Explanation:

Given equation is C=
(5)/(9)(F -32)

Ans A).

For the table,

Take the four value of F as 32,41,50,59.

For F = 32.

The value of C is

C=
(5)/(9)(F -32)

C=
(5)/(9)(32 -32)

C=0.

For F = 41.

The value of C is

C=
(5)/(9)(F -32)

C=
(5)/(9)(41 -32)

C=05

For F = 50.

The value of C is

C=
(5)/(9)(F -32)

C=
(5)/(9)(50 -32)

C=10

For F = 59.

The value of C is

C=
(5)/(9)(F -32)

C=
(5)/(9)(32 -32)

C=15

Note: The figure shows a graph of given equation with points.

Ans B). Estimate temperature in C when the temperature in F is 65

For F = 65.

The value of C is

C=
(5)/(9)(F -32)

C=
(5)/(9)(32 -32)

C=18.333333.

Ans C). At what temperature, graph lien cross the horizontal axis

When the line crosses the horizontal axis, C=0

Therefore,

C=
(5)/(9)(F -32)

0=
(5)/(9)(F -32)

0=
(F -32)

F=32 Temperature.

Ans D). Slope of the line C=
(5)/(9)(F -32)

The slope of line is given by s=
(Y1-Y2)/(X1-X2)

Take points from the table of answer A.

let (32,0) and (41,5) using for slope.

s=
(Y1-Y2)/(X1-X2)

s=
(0-5)/(32-41)

s=
(5)/(9)

Slope of line C=
(5)/(9)(F -32) is
(5)/(9)

Does anyone understand this?. I also have to show my work.-example-1
User Winerd
by
7.5k points