Question

What is the centripetal acceleration of the earth as it travels around the sun when Earth has an orbital radius of 1.5 x 10^11 m and an average orbital speed of 29.7 km/s

Answer 1

Answer:
`0.0058 m/s^(2)`

Step-by-step explanation:

Centripetal acceleration
`a_(C)` is calculated by the following equation:

`a_(C)=(V^(2))/(r)`

Where:

`V=29.7 (km)/(h) (1000 m)/(1 km)=29700 m/s` is the Earth's orbital speed

`r=1.5(10)^(11) m` is the orbital radius

`a_(C)=((29700 m/s)^(2))/(1.5(10)^(11) m)`

`a_(C)=0.0058 m/s^(2)`