Answer:
The vehicle travels 56.25 metres in the interval during which body decelerates .
Step-by-step explanation:
- Initial velocity of vehicle, u = 32 m/s
- Final velocity of vehicle, v = 22 m/s
- Rate of acceleration, a = - 4.8 m/
![s^(2)](https://img.qammunity.org/2020/formulas/physics/middle-school/6tzd9jx3jcbjv5zphhkqd2l52b24mrknt6.png)
Let the distance travelled be s .
We have to determine the distance travelled by the vehicle during this time.
The equation of motion is given by
![v^(2) - u^(2) = 2 * a * s](https://img.qammunity.org/2020/formulas/physics/high-school/h22ewewfu8z8brk0ednhevo4b5c7e51ovv.png)
![(22)^(2) - (32)^(2) = 2 * (- 4.8) * (s)](https://img.qammunity.org/2020/formulas/physics/high-school/bb9pknfqxyxco1pyc38puybn6licqorfsf.png)
![1024 - 484 =9.6 * (s)](https://img.qammunity.org/2020/formulas/physics/high-school/98j5ifpkkrfynuic5krhn8pmbj3rhzh51l.png)
s =
![(540)/(9.6)](https://img.qammunity.org/2020/formulas/physics/high-school/uj71zu87alg9vccxkuy97gqc0lj5codl01.png)
s = 56.25 metres
The vehicle travels 56.25 metres in the interval during which body decelerates .