Question

Solve using long division.

(3x^2+7x-20) / (x+4)

please show work on paper pls, it'll be more helpful

Answer 1

Quotient is
`3x-5` and remainder is 0.

Explanation:

Given:

Dividend =
`3x^2+7x-20`

Divisor =
`x+4`

The long division is shown in the attachment.

Step 1: we need to divide
`3x^2+7x-20` with
`x+4` we first multiply
`x+4` with 3x we get the remainder as
`-5x-20`

Quotient as 3x.

Step 2: Now the dividend is
`-5x-20` and divisor
`x+4` now we will multiply
`x+4` with -5 we get the remainder as 0 and Quotient as
`3x-5`

Hence Quotient is
`3x-5` and remainder is 0.