Question

What are the zeroes of f(x)=x+5-2x^2

Answer 1

The zeros of the function are x = -1.35 and x = 1.85

Explanation:

The given function is f(x) = x + 5 - 2x²

⇒ f(x) = - 2x² + x + 5

To find the zeroes of the function we are assuming f(x) = 0 and solve the equations.

Hence, - 2x² + x + 5 = 0

Applying Sridhar Acharya's formula

`x = \frac{-1 + \sqrt{1^(2) - 4 (- 2)(5) } }{2(- 2)}` and
`x = \frac{-1 - \sqrt{1^(2) - 4 (- 2)(5) } }{2(- 2)}`

⇒
`x = (- 1 + 6.4)/(-4)` and
`x = (- 1 - 6.4)/(-4)`

⇒ x = -1.35 and x = 1.85

Therefore, the zeros of the function are x = -1.35 and x = 1.85 (Answer)