Question

How much heat is required to raise the temperature of

50.00 g of liquid water from 15°C to gaseous water at
100°C? (Heat of vaporization of water is 2260.0 J/9)

Answer 1

The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .

Explanation:

Given as :

The mass of liquid water = 50 g

The initial temperature =
`T_1` = 15°c

The final temperature =
`T_2` = 100°c

The latent heat of vaporization of water = 2260.0 J/g

Let The amount of heat required to raise temperature = Q Joule

Now, From method

Heat = mass × latent heat × change in temperature

Or, Q = m × s × ΔT

or, Q = m × s × (
`T_2` -
`T_1` )

So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )

Or, Q = 50 g × 2260.0 J/g × 85°c

∴ Q = 9,605,000 joule

Or, Q = 9,605 × 10³ joule

Or, Q = 9605 kilo joule

Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer