Question

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places where appropriate.)

sin(θ) = −sqrt/ 3/ 2

Answer 1

θ = {(4/3 +2k)π, (5/3 +2k)π}

Explanation:

From your knowledge of trig functions, you know that sin(60°) = sin(π/3) = (√3)/2. So, the angles of interest are in the 3rd- and 4th-quadrant and will have π/3 as their reference angle.

θ = 4/3π +2kπ, and 5/3π +2kπ