Question

(PYTHON HOMEWORK)Given the following code snippet, which statement tests to see if all three sets are equal?:

fruit = set(["apple", "banana", "grapes", "kiwi"])
fruit2 = set(["apple", "banana", "grapes", "kiwi"]
fruit3 = set(["apple", "banana", "pears", "kiwi"])

A. if fruit.equal(fruit2) and fruit.equal(fruit3) :

B. if fruit != fruit2 and fruit != fruit3 :

C. if fruit == fruit2 and fruit == fruit3 :

D. if fruit == fruit2 or fruit == fruit3 :

This is NOT from a freaking exam geez. Exams are already over in Florida for dual enrollment classes and this python class doesn't even have tests or exams.

Answer 1

Option D is the correct answer to the following question.

Step-by-step explanation:

The following option is correct because three sets type variable i.e., "fruit", "fruit2", "fruit3" has contain the same values in it and then they ask for the option is correct if the all are equal and in the option c, there is the if statement in which check the condition if the variable "fruit" is equal to the variable "fruit2" and the variable "fruit" is equal to the variable "fruit3".

so, that' why the following option is correct.

The option A is not correct because there is no equal function in python and we use the operator == to check the condition.

The option B is incorrect because we can see that there is not equal to (!=) operator.

The option D is incorrect because we can see that there is an or operator are used which means if any of the conditions is true then, they return either the other condition is false.