Question

An object is dropped from the top of a building and strikes the ground 2.0s later How tall is the building?

Answer 1

the height of the building will be 19.6 meters.

Step-by-step explanation:

writing equation of motion in vertical direction:

`s=ut-(1)/(2)gt^(2)`

where u is initial velocity of the object which is equal to 0

and g is the acceleration due to gravity g = 9.8m/
`s^(2)`

therefore the equation becomes

`-h=-(1)/(2)gt^(2)`

h=
`(1)/(2)9.8* 2^(2)`=19.6 meters