Question

An object is at rest when it undergoes a constant acceleration of 13 m/s ^ 2 for 5.0 seconds. How far will it have traveled during this time?

Answer 1

162.5 m is the distance traveled by an object.

Step-by-step explanation:

Given that,

An object's constant acceleration (a) is
`13m/s^2`.

The time (t) it traveled is 5 seconds.

The object is at rest that is "initial velocity" (u) is 0 m/s.

To find the distance traveled use the below formula,

`s=ut+(1)/(2)at^2`

Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.

Substitute the given values in the above formula,

`s=0*5+(1)/(2)*13* 5^2`

`s=0+(1)/(2)*13* 25`

`s=0+(1)/(2)*325`

s = 162.5 m

Therefore, distance traveled is 162.5 m.