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Equation perpendicular to y=-2x+5 and goes through point (-3,4)

1 Answer

2 votes

Answer:

y =
(1)/(2) x +
(11)/(2)

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 2x + 5 ← is in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(-2) =
(1)/(2), thus

y =
(1)/(2) x + c ← is the partial equation

To find c substitute (- 3, 4) into the partial equation

4 = -
(3)/(2) + c ⇒ c = 4 +
(3)/(2) =
(11)/(2)

y =
(1)/(2) x +
(11)/(2) ← equation of perpendicular line

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