Question

The perimeter of the flag is 2080 ft what is the flags width and length of the length is 420 ft greater than the width

Answer 1

The length of the flag is 730 ft and the width is 310 ft

Explanation:

The correct question is

The perimeter of the flag is 2080 ft what is the flags width and length if the length is 420 ft greater than the width

Let

L ----> the length of the flag

W ---> the width of the flag

we know that

The perimeter of the flag (rectangle) is equal to

`P=2(L+W)`

we have

`P=2,080\ ft`

so

`2,080=2(L+W)`

`1,040=L+W` ----> equation A

`L=W+420` ---> equation B

Solve the system by substitution

substitute equation B in equation A

`1,040=(W+420)+W`

solve for W

`1,040=2W+420`

`2W=1,040-420`

`2W=620`

`W=310\ ft`

Find the value of L

`L=W+420` ---->
`L=310+420=730\ ft`

therefore

The length of the flag is 730 ft and the width is 310 ft