Question

95i is a root of f(x)=x^2 +9025. find the other roots of f(x)

Answer 1

Other root is -95i

Explanation:

Here, Nature of roots of f(x) is imaginary roots.

Therefore, Roots are conjugate of each other.

Conjugate of x + yi is x - yi.

we get conjugate of 95i as -95i

Verification shows....

(x-95)(x+95i)=0

`{x }^(2) - {95}^(2) {i}^(2) = 0 \\ {x }^(2) + {95}^(2) = 0 \\ {x }^(2) + 9025= 0 \\ f(x) = 0`

this, roots are -95i and 95i