Question

A force of 40N is applied at the end of a wire 4m long and produce an extension of 0.24mm if the diameter of the wire is 2mm. calculate the stress and strain of the wire​

Answer 1

The stress of the wire is 12.74 MPa and the strain is 0.006%.

Step-by-step explanation:

To calculate the stress of the wire, we divide the force (40N) by the cross-sectional area of the wire. The diameter of the wire is given as 2mm, so the radius is 1mm or 0.001m. Using the formula for the area of a circle (A = πr^2), the cross-sectional area of the wire is 3.14 x (0.001)^2 = 3.14 x 0.000001 = 0.00000314 m^2. Dividing the force (40N) by the cross-sectional area (0.00000314m^2), we get a stress of 40N / 0.00000314m^2 = 12,738,852.87 N/m^2 or 12.74 MPa (megapascals).

To calculate the strain of the wire, we divide the extension (0.24mm) by the original length of the wire (4m). The strain is given as a percentage, so we multiply by 100. The strain is (0.24 / 4000) * 100 = 0.006%

Answer 2

If a force of 40newton is applied to the end of a wire 4m long and produces an extension of 0.24mm. If the diameter of the wire is 2mm, calculate the strain energy

Step-by-step explanation:

stress=force/area (n/m^2)

strain=deformation/length (m/m)