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The ratio of black pens to blue pens in Mark's drawer is 4 to 3. If Mark has more than 40 pens, what is the minimun number of pens that can be in Mark's drawer?

User Exsnake
by
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1 Answer

3 votes

Answer:

The minimum number of black pens the drawer is 23 and The minimum number of blue pens in the drawer is 17 .

Explanation:

Given as :

The ratio of black pen to blue pen in drawer = 4 : 3

Let The minimum number of black pen = 4 x

And The minimum number of blue pen = 3 x

The total number of pens in drawer = more than 40

So, According to question

∵ The total number of pens in drawer
> 40

So, 4 x + 3 x
> 40

Or, 7 x
> 40

∴ x
>
(40)/(7)

I.e x
> 5.71

So, The minimum number of black pen = 4 × 5.7 = 22.8 ≈ 23

And The minimum number of blue pen = 3 × 5.7 = 17.1 ≈ 17

Hence The minimum number of black pens the drawer is 23 and The minimum number of blue pens in the drawer is 17 . Answer

User Ben Rowe
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