The co-ordinates of point R is (6 , 2)
Solution:
Given that M(7, 3) is the midpoint of RS
Also co-ordinates of point S is (8, 4)
To find: co-ordinates of point R
The midpoint of two points
and
is given as:
![M=\left((x_(1)+x_(2))/(2), (y_(1)+y_(2))/(2)\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/26xig8vob7llknocsq89ifqfib8orkofgn.png)
Here midpoint M = (7, 3) and point S
![(x_1 , y_1) = (8, 4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t6ynwv2tc0xq92zhhpa9d7zpqbf6sxwlvc.png)
Point R =
![(x_2, y_2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xwnno164w0xmr4pzaq8p6mvc6epijbto1t.png)
Substituting the values in formula we get,
![(7,3)=\left((8+x_(2))/(2), (4+y_(2))/(2)\right)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b8y2igtssvsedhikjz3wol9vfvxxn4kzy7.png)
Comparing both the sides we get,
and
![(4+y_(2))/(2)=3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7n8k3oatjmqvxb2m8t7ew0q1vwrt2h05zj.png)
On solving,
![\begin{array}{l}{14=8+x_(2)} \\\\ {x_(2)=6}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/m63gckc0sscgaltp0bnee4xb7xblz8s844.png)
Also,
![\begin{array}{l}{4+y_(2)=6} \\\\ {y_(2)=2}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5bq4t88kq7y3ppvjf963f5riq65e6bmtmp.png)
Thus the co-ordinates of point R is (6 , 2)