Answer:
1·276 g/L
Step-by-step explanation:
Given
Number of moles of gas = 0·043
Mass of the gas = 1·892 g
Temperature of the gas = 273 K
Pressure of the gas = 0·65 atm
Assuming that the gas is ideal
Ideal gas equation is P × V = n × R × T
where
P is the pressure of the gas
V is the volume occupied by the gas
n is the number of moles of the gas
R is the ideal gas constant
T is the temperature of the gas
Let the volume of the gas be V L
From ideal gas equation
0·65 × V = 0·043 × 0·0821 ×273
∴ V = 1·483 L
Density is defined as mass per unit volume
Let the density of the gas be d g/L
∴ d = (mass of the gas) ÷ (volume of the gas)
d = 1·892 ÷ 1·483
∴ d ≈ 1·276 g/L
∴ Density of the gas at the given conditions is 1·276 g/L