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Find the reminder of the division
(8^33):6

1 Answer

4 votes

Answer:

The remainder is 2.

Explanation:

Use modular arithmetic.

If the remainder is x then 8^33 mod 6 = x.

8^3 = 512 = 2 mod 6

8^6 = (8^3 * 8^3) mod 6 = (2*2) mod 6 = 4 mod 6

8^30 mod 6 = (8^6)^5 mod 6 = 4^5 mod 6 = 1024 mod 6

= 4 mod 6.

Finally 8^33 mod 6 = (8^3 * 8^30) mod 6 = (2 * 4) mod 6

= 8 mod 6 = 2.

User Janlindso
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