Question

Writing the quation for a line that goes through the following points (0,3) (1,1

Answer 1

`\huge\boxed{y=-2x+3}`

Start off by finding the slope of the line with the formula
`(y_2-y_1)/(x_2-x_1)`.

Substitute the values.
`(1-3)/(1-0)`

Subtract.
`(-2)/(1)`

Simplify.
`-2`

`-2` is the slope of the line.

Now, use the point-slope formula to create an equation, where
`m` is the slope and
`(x_1, y_1)` is a known point on the line.
`y-y_1=m(x-x_1)`

Substitute the values.
`y-3=-2(x-0)`

Simplify.
`y-3=-2x`

Move the
`3` to create the final equation in slope-intercept form.
`\large\boxed{y=-2x+3}`