Question

Ammonium phosphate NH43PO4 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid H3PO4 with ammonia NH3.

What mass of ammonium phosphate is produced by the reaction of 7.1g of phosphoric acid?

Round your answer to 2 significant digits.

Answer 1

The mass of ammonium phosphate produced by the reaction of 7.1g of phosphoric acid is 52.0 g.

Step-by-step explanation:

To determine the mass of ammonium phosphate produced, we need to use stoichiometry and the balanced equation:

2H3PO4 + 3NH3 → (NH4)3PO4

The molar mass of H3PO4 is 98 g/mol.

Using the molar ratio from the balanced equation, we can set up the following calculation:

(7.1g H3PO4) x (1 mol H3PO4/98 g H3PO4) x (1 mol (NH4)3PO4/2 mol H3PO4) x (149 g (NH4)3PO4/1 mol (NH4)3PO4) = 52.0 g (NH4)3PO4

Therefore, the mass of ammonium phosphate produced is 52.0 g.

Answer 2

The weight of ammonium phosphate is 10 gm

Step-by-step explanation:

The chemical reaction of ammonium phosphate formation is as follows.

`3NH_(3)+H_(3)PO_(4) \rightarrow [(NH_(4))_(3)PO_(4)]`

From the reaction one mole of phosphoric acid is equivalent to the one mole of ammonium phosphate.

So, "n" mole of phosphoric acid is equivalent to the "n" mole of ammonium phosphate.

Number of moles in 7.1 grams of phosphoric acid =
`(7.1)/(Molarmass\,of phosphoric\,acid)`

`(7.1)/(98)= (1)/(13.8)`

Formation weight of ammonium phosphate :

Weight of ammonium phosphate =
`= (1)/(13.8)* Molarmass\,of\,\,ammonium\,phosphate`

`=(149)/(13.8) = 10.79gm`

Round the answer to 2 significant digits

Weight of ammonium phosphate = 10 gm