Question

Can someone please answer do this for me

Answer 1

Ans16.

a=500$

r=R/100=3.5/100=0.035

`A(t)=500(1.035)^(t)`

Ans17. for table,

For x=4, y=573.761

For x=5, y=593.843

For x=6, y=614.627

For x=7, y=636.139

For x=8, y=658.404

Ans18.

After t=7.6238 years.

Explanation:

You invest $500 in a savings account that pays 3.5% annual interest

The compound interest is given by
`A(t)=a(1+(R)/(100) )^(t)`

Where, a=Principal amount, t= number of year, R= Rate of interest and

A(t)= Principal amount + Interest

16. Compare the model:

The compound interest is given by
`A(t)=a(1+(R)/(100) )^(t)`

Given that a=500$

and Rate of interest R=3.5

Therefore r=R/100=3.5/100=0.035

Also,
`A(t)=a(1+(R)/(100) )^(t)`

`A(t)=500(1+0.035)^(t)`

`A(t)=500(1.035)^(t)`

17. Using the Table:

Take x=t and y=A(t)

For x=4,

`y=500(1.035)^(4)`

`y=573.761`

Similarly,

For x=5, y=593.843

For x=6, y=614.627

For x=7, y=636.139

For x=8, y=658.404

18. Amount A(t) will count 650$ when t=?

Using given equation,

`A(t)=500(1.035)^(t)`

`650=500(1.035)^(t)`

Take log both side,

`log(1.3)=t * log(1.035)`

`0.1139=t * 0.01494`

t=7.6238 years.