Question

Write and equation in standard form for a line that is (a) parallel (b) perpendicular to the line with an equation of y= 3x - 5 that passes through the point (5,8)

Answer 1

(a) 3x -y = 7

(b) x +3y = 29

Explanation:

(a) The standard form of the given line is ...

3x -y = 5

The parallel line will have a constant on the right that makes it go through (5, 8), so it will be ...

3x -y = 3(5) -(8)

3x -y = 7

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(b) The perpendicular line will have coefficients for x and y swapped and one of them negated. Again, the constant is chosen to make it go through (5, 8).

x + 3y = (5) +3(8)

x + 3y = 29