50.1k views
4 votes
Please help with this simple trig problem- angle of two sectors of a circle

Please help with this simple trig problem- angle of two sectors of a circle-example-1
User Zach Smith
by
7.6k points

1 Answer

3 votes

Answer:

K = (1/2)r^2(sin(θ) +θ)

Explanation:

The area of the triangle to the left is ...

A1 = (1/2)r^2·sin(180°-θ) = (1/2)r^2·sin(θ)

The area of the sector to the right is ...

A2 = (1/2)r^2θ

so the total area of the blue shaded region is ...

K = A1 + A2 = (1/2)r^2·sin(θ) + (1/2)r^2·θ

K = (1/2)r^2(sin(θ) +θ)

User Sterling Nichols
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories