50.1k views
4 votes
Please help with this simple trig problem- angle of two sectors of a circle

Please help with this simple trig problem- angle of two sectors of a circle-example-1
User Zach Smith
by
6.0k points

1 Answer

3 votes

Answer:

K = (1/2)r^2(sin(θ) +θ)

Explanation:

The area of the triangle to the left is ...

A1 = (1/2)r^2·sin(180°-θ) = (1/2)r^2·sin(θ)

The area of the sector to the right is ...

A2 = (1/2)r^2θ

so the total area of the blue shaded region is ...

K = A1 + A2 = (1/2)r^2·sin(θ) + (1/2)r^2·θ

K = (1/2)r^2(sin(θ) +θ)

User Sterling Nichols
by
6.1k points