Question

How do I go about simplifying this equation? (Using i =
`√(-1)`)


`√(-3)\cdot \:2i√(8)\left(-2\right)√(-2)i^(88)`

Answer 1

16i√3

Explanation:

I would write the radicals of negative numbers in terms of i, combine factors outside the radicals and combine factors inside the radicals. The power of i can be rewritten as a power of a power.

`=i√(3)\cdot 2i√(8)(-2)i√(2)\cdot i^(88)\\\\=(2)(-2)√((3)(8)(2))\cdot i^(91)\\\\=-4√(48)\cdot (i^2)^(45)\cdot i\\\\=-16√(3)(-1)^(45)\cdot i\\\\=16i√(3)`