Question

Consider the reversible reaction in aqueous medium shown below. At equilibrium, the concentrations of A, B, C, and D are 0.0053 M, 0.0085 M, 0.0040 M, and 0.0035 M, respectively. What is the equilibrium constant for the reaction? A+3B⇌3C+D

Answer 1

The equilibrium constant for the reaction is 0.0689

Step-by-step explanation:

Step 1: Data given

The concentrations of A = 0.0053 M

The concentration of B = 0.0085 M

The concentration of C = 0.0040 M

The concentration of D = 0.0035 M

Step 2: The balanced equation:

A+3B⇌3C+D

Step 3: Calculate the equilibrium constant

K = [C]³[D] / [A][B]³

K = (0.0040)³(0.0035) / (0.0053)(0.0085)³

K = 0.0689

The equilibrium constant for the reaction is 0.0689