Question

Disregarding wind resistance the distance a body falls from rest varies directly as th squares of the time it falls if a skydiver falls 64ft in 2 seconds, how far will he fall in 10 seconds

Answer 1

The skydiver will fall 1600 ft in 10 seconds.

Explanation:

Distance a body falls from rest varies directly as the squares of the time it falls

Let distance = s

time = t

Therefore , s = k
`* t^(2)`

Given, the body falls 64 ft in 2 seconds.

Substituting in above equation,

64 = k
`* (2)^(2)`

64 = k
`* (4)`

k =
`(64)/(4)`

k = 16 ft/
`s^(2)`

We have to find how much he will fall in 10 seconds.

s = k
`* t^(2)`

s =
`16 * 10^(2)`

s =
`16 * 100`

s = 1600 ft