Question

Write an equation of the line that passes through the given point and is parallel to the given line.

Use this equation:

(-5, -2); y= 2/3x + 1

Answer 1

Answer : Equation of line is y=Equation of line is y=
`(2)/(3)`x+
`(-5)/(3)`

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y =
`(2)/(3)`x+1 is m=
`(2)/(3)`

We know that line : y =
`(2)/(3)`x+1 is parallel to equation of target line.

therefore, slope of target line will be
`(2)/(3)`.

we write equation of target line as y=
`(2)/(3)`x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y=
`(2)/(3)`x+c

-2=
`(2)/(3)`
`*` -5+ c

-5=
`(-10)/(3)`+c

c=
`(-5)/(3)`

thus, Equation of line is y=Equation of line is y=
`(2)/(3)`x+
`(-5)/(3)`