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1 vote
Write an equation of the line that passes through the given point and is parallel to the given line.

Use this equation:

(-5, -2); y= 2/3x + 1

1 Answer

5 votes

Answer : Equation of line is y=Equation of line is y=
(2)/(3)x+
(-5)/(3)

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y =
(2)/(3)x+1 is m=
(2)/(3)

We know that line : y =
(2)/(3)x+1 is parallel to equation of target line.

therefore, slope of target line will be
(2)/(3).

we write equation of target line as y=
(2)/(3)x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y=
(2)/(3)x+c

-2=
(2)/(3)
* -5+ c

-5=
(-10)/(3)+c

c=
(-5)/(3)

thus, Equation of line is y=Equation of line is y=
(2)/(3)x+
(-5)/(3)

User Upasana Mittal
by
7.6k points

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