Answer:
0.065 M
Step-by-step explanation:
Volume of H₃PO₄ solution (V1) = 5.40 mL
Volume of NaOH solution (V2) = 7.02 mL
Molarity of NaOH solution (M2) = 5 × 10⁻² M
Molarity of H₃PO₄ solution (M1) = ?
Solution:
It is a acid base titration
Formula to be used
M1V1 = M2V2
Put values in above equation
M1 x 5.40 mL = 5 × 10⁻² M x 7.02 mL
Rearrange the above equation
M1 = 5 × 10⁻² M x 7.02 mL / 5.40 mL
M1 = 0.065 M
So the Molarity H₃PO₄= 0.065 M