Question

A sailboat started its trip at an average speed of 50 mph at

13.15. If the distance of the trip was 510 miles, at what time did
the sailboat reach its destination?
(Enter your answer in 24 hr tin

Answer 1

The sailboat will reach the destination at 23:27

Step-by-step explanation:

let the velocity of the sail boat be U and time to reach the destination be t.

therefore its is given that u = mph

and the distance to be covered S = 510 miles

we know that S = Ut+ \frac{1}{2}×a×t^{2}

here we have acceleration a = 0

therefore 510 = 50×t

t = \frac{510}{50} hours

t = 10.2 hours

0.2 hours = \frac{2}{10}\times 60 seconds

12 minutes

therefore total time taken = 10 hours 12 minutes

therefore the sailboat will reach the destination at 23:27

Answer 2

The sailboat will reach the destination at 23:27.

Step-by-step explanation:

Distance traveled = 510 miles

Average speed = 50 miles per hour

We know that ,

Distance = speed × time

And hence Time taken will be = 510÷50

= 10.2 hours.

= 10 hours and 12 minutes (0.2×60 minutes)

Since the sail boat started at 13:15, and will take 10 hours and 12 minutes to complete the journey, It will reach the destination at 23:27.