Answer:
After adding 46.4 J of heat, the final temperature of aluminium is 28.396 ( The temperature difference is 3.396 °C).
The final temperature of berylium is 26.677 ( the temperature difference is 1.677°C)
Step-by-step explanation:
Step 1: Data given
Mass of aluminium = 15.2 grams
Mass of berylium = 15.2 grams
Temperature = 25.0°C
46.4 J of heat is added
The specific heat for Al = 0.899 J/g °C
The specific heat for Be=1.82 J/g °C
Step 2: Calculate the final temperature of aluminium
Q = m*c*ΔT
⇒ Q = the heat in Joule = 46.4 J
⇒ m = the mass of Aluminium = 15.2 grams
⇒ c= the specific heat of aluminium = 0.899 J/g°C
⇒ ΔT = The change in temperature = T2 - T1 = T2 - 25.0 °C
46.4 J = 15.2g * 0.899 J/g°C * (T2-25.0 °C)
46.4 = 13.6648(T2 - 25.0°C)
46.4 = 13.6648T2 - 341.62
388.02 = 13.6648T2
T2 = 28.396 °C
Step 3: Calculate the final temperature of berylium
Q = m*c*ΔT
⇒ Q = the heat in Joule = 46.4 J
⇒ m = the mass of Aluminium = 15.2 grams
⇒ c= the specific heat of aluminium = 1.82 J/g°C
⇒ ΔT = The change in temperature = T2 - T1 = T2 - 25.0 °C
46.4 J = 15.2g * 1.82 J/g°C * (T2-25.0 °C)
46.4 = 27.664(T2 - 25.0)
46.4 = 27.664T2 - 691.6
738 = 27.664T2
T2 = 26.677 °C
After adding 46.4 J of heat, the final temperature of aluminium is 28.396 ( The temperature difference is 3.396 °C).
The final temperature of berylium is 26.677 ( the temperature difference is 1.677°C)