complete question:
Two cars raced at a race track. The faster car traveled 20 mph faster than the slower car. In the time that the slower car traveled 165 miles, the faster car traveled 225 miles. If the speeds of the cars remained constant, how fast did the slower car travel during the race?
Answer:
The slower car traveled 55 mph
Explanation:
Let
Speed of the slower car = a mph
Speed of the faster car = (a + 20) mph
The speed of the car remains constant when the both cars covers different distance.
slower car
speed = distance/time
time = distance/speed
time = 165/a
faster car
time = distance/speed
time = 225/(a + 20)
t = t
165/a = 225/(a + 20)
cross multiply
165(a + 20) = 225a
165a + 3300 = 225a
collect like terms
3300 = 225a - 165a
60a = 3300
divide both sides by 60
a = 3300/60
a = 55 mph
The slower car traveled 55 mph