Question

Find the change in velocity of a 369 g hockey puck subject to the force shown below.

Answer 1

The student's question is about calculating the change in velocity for a hockey puck in a physics context, but it lacks necessary details like the force applied or the duration. Once provided, one can apply principles from mechanics to obtain the answer. The question involves concepts from physics, specifically mechanics and collisions.

Step-by-step explanation:

The student's question involves calculating the change in velocity of a hockey puck subject to a force. This is a classic problem in the field of Physics, specifically within the subtopic of mechanics. The question relates to the concepts of momentum, collisions, and possibly Newton's second law, depending on the details provided in the question or supplementary materials.

To solve such a problem, one would typically use the principle of conservation of momentum to determine the final velocities of objects after a collision, or apply Newton's second law if a force and time period are given. However, since the question lacks specific details about the force applied or the time over which it was applied, we cannot give a numerical answer. If additional information is provided, such as the force exerted and duration of the force, one could use the formula change in momentum (Δp) = force (F) × time (Δt), and since change in velocity (Δv) = Δp / mass (m), we can find Δv.

Answer 2

The change in velocity is 15.83 [m/s]

Step-by-step explanation:

Using the Newton's second law we have:

ΣF = m*a

The force in the graph is 185 N, therefore:

`185=0.369*a\\Where\\a=acceleration made it by the force [m/s^2]`

`a=501.35[m/s^2]`

Now using the following kinematic equation:

`V^(2)=Vi^(2) + 2*a*(x-xi) \\where\\V=final velocity [m/s]\\Vi= initial velocity [m/s] = 0 the hockey disk is in rest when receives the hit.\\ x = Final position [m] = 0.4 m\\xi = initial position [m] = 0.15m\\`

Now replacing the values:

`V^(2)=0 + 2*501.35*(0.4-0.15)\\ \\V= 15.83[m/s]`