Answer:
The height of rectangle is 5 inches
Explanation:
The correct question is
A rectangle is drawn so the width is 7 inches longer than the height. If the rectangle’s diagonal measurement is 13 inches, Find the height
Let
x -----> the width of the rectangle in inches
y ----> the height of the rectangle in inches
d ---> diagonal measurement of the rectangle in inches
we know that
Applying the Pythagorean Theorem
![d^2=x^(2)+y^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4jkjjdvvw2cfprkrtcoj3l98loj144tvy3.png)
we have
![d=13\ in](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8bv9tgglfm2meg9ttcnrzfby2qt4ry5ioh.png)
so
![13^2=x^(2)+y^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/204wdnyfqdmh3rfewc7u061vbbp3jpo373.png)
----> equation A
---> equation B
substitute equation B in equation A
![169=(y+7)^(2)+y^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/viqqy3udvcm0l87bjfummf7qipwywi8pev.png)
solve for y
![169=y^2+14y+49+y^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kvjvxyfc1rmy6lp1q58gcth359nyxi225f.png)
![2y^2+14y+49-169=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c6h7psdvhnrv5ji6jcfx3521qbl7dz24yb.png)
![2y^2+14y-120=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/et7qtszr3qp4981h1hyrw1fsrp7c9n36hc.png)
solve the quadratic equation by graphing
using a graphing tool
The solution is y=5
see the attached figure
therefore
The height of rectangle is 5 inches